std::copy_n
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| definiert in Header <algorithm>
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| template< class InputIt, class Size, class OutputIt > OutputIt copy_n( InputIt first, Size count, OutputIt result ); |
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Copies exactly count values from the range beginning at first to the range beginning at result, if count>0. Does nothing otherwise.
Inhaltsverzeichnis |
[Bearbeiten] Parameter
| first | - | the beginning of the range of elements to copy from |
| count | - | number of the elements to copy |
| result | - | der Beginn des Zielbereichs
Original: the beginning of the destination range The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| Type requirements | ||
-InputIt must meet the requirements of InputIterator.
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-OutputIt must meet the requirements of OutputIterator.
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[Bearbeiten] Rückgabewert
Iterator in the destination range, pointing past the last element copied if count>0 or first otherwise.
[Bearbeiten] Komplexität
Exactly count assignments, if count>0.
[Bearbeiten] Mögliche Implementierung
template< class InputIt, class Size, class OutputIt> OutputIt copy_n(InputIt first, Size count, OutputIt result) { if (count > 0) { *result++ = *first; for (Size i = 1; i < count; ++i) { *result++ = *++first; } } return result; } |
[Bearbeiten] Beispiel
#include <iostream> #include <string> #include <algorithm> #include <iterator> int main() { std::string in = "1234567890"; std::string out; std::copy_n(in.begin(), 4, std::back_inserter(out)); std::cout << out << '\n'; }
Output:
1234
[Bearbeiten] Siehe auch
| (C++11) |
Kopiert einen Bereich von Elementen, um eine neue Position Original: copies a range of elements to a new location The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (Funktions-Template) |
