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json returns years in this format

"dateOfBirth":"1997-03-23T08:00Z"

I need to convert the years to this format

var bDate = "3/23/1997";
var bDateformat = new Date(bDate).getTime() / 1000 | 0;
console.log("Birthday: "+bDateformat);

so in example i get returned value of

859093200
5
  • 1
    What's the actual question? Commented May 5, 2022 at 12:46
  • If it's how to convert seconds into years, then just: Math.floor(bDateformat / 31557600) Commented May 5, 2022 at 12:47
  • The Date constructor understands the format YYYY-MM-DD as well, so just cut off the T08:00Z part from your input date ...? (It would understand the full 1997-03-23T08:00Z as well, but if you are passing in a specific time as well, your result in seconds will of course slightly differ.) Commented May 5, 2022 at 12:47
  • ok , thanks , how can i trim off the part not needed ? Commented May 5, 2022 at 12:49
  • var bDate = "3/23/1997"; -> Read What are valid Date Time Strings in JavaScript? Commented May 5, 2022 at 12:53

2 Answers 2

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You can use this to output in JSON format:

var bDate = "3/23/1997";

new Date(bDate ).toJSON()
// result: '1997-03-22T19:30:00.000Z'

Or you can use this to get the date object from the JSON string:

var bDate = '1997-03-22T19:30:00.000Z';

new Date(bDate).toLocaleString()
// result: '3/23/1997, 12:00:00 AM'
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This was also my question before, I have easily overcome this by using the Moment.js. It is easy to use and very understandable. Also, you can easily convert the patterns all together very simply.

Documentation on Moment.js

I don't know if your project is HTML and Javascript (or you are using node or ...), you can simply download (or install the package) the Moment.js and after including it in your project, the only thing you need to do is:

var bDate = "1997-03-23T08:00Z"
var newBDate = moment(bDate, "YYYY-MM-DDTHH:mm[Z]").format('M/DD/YYYY');
//Or you can use any other final date format as you want
console.log(newBDate)

This will help users to easily convert to any time format they want.

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