Greater than or not equal to

Question

My code here

if (parent4 && parent5 && parent6 && (_state[tree][parent4]) + (_state[tree][parent5]) + (_state[tree][parent6]) !== 8) {
  return false;
} else {
  return true;
}

It works, and has some of the elements I want, namely that if the sum of the three _states !== 8, it returns false.

I'll try to explain the logic I'm trying to achieve as simply as I can:

if par4 + par5 + par6 !>= 8
  return false

if par4 + par5 !>= 8
  return false

if par4 OR par5 OR par6 !>= 8
  return false

else
  return true

I abbreviated the code for simplicity and ease of understanding.

Swapping around return false and return true and changing it to >= doesn't work, because for all elements, even ones I don't mention here, it needs to go to return true by default.

Entire expression in single parentheses -> (_state[tree][parent4] + _state[tree][parent5] + _state[tree][parent6]) !== 8 — Anurag Srivastava
– Anurag Srivastava, Commented Mar 27, 2020 at 16:24
I'll rephrase sorry, not greater than or equal to so to write it out !>= 8 it should return false, else return true. — helpless123
– helpless123, Commented Mar 27, 2020 at 16:34
if par4 + par5 !>= 8 what would !>= 8 mean? "Not greater or equal to"? Because that is "less than". If it's "not equal AND greater or equal" then that's just "greater than". — VLAZ
– VLAZ, Commented Mar 27, 2020 at 16:34
That makes some sense, however replacing the "!==" with "greater than" doesn't seem to work. Then it returns false whenever the sum is "greater than" I need it return true whenever the sum is "greater than" and in all other cases. — helpless123
– helpless123, Commented Mar 27, 2020 at 16:39

Dave · Accepted Answer · 2020-03-27 16:29:26Z

1

How about this?

if (parent4 && parent5 && parent6) {
    if ((_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
        return false;
    } else {
        return true;
    }
}

Or in a one-liner:

if (parent4 && parent5 && parent6 && (_state[tree][parent4] + _state[tree][parent4] + _state[tree][parent4]) !== 8) {
    return false;
} else {
    return true;
}

answered Mar 27, 2020 at 16:29

Dave

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2 Comments

VLAZ Over a year ago

Isn't the oneliner what OP already has but with the brackets placed differently (which wouldn't affect the logic)?

Dave Over a year ago

You're right. I wouldn't think it should affect anything. Actually not sure why the OP code isn't working.

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