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Questions tagged [special-functions]

This tag is for questions on special functions, useful functions that frequently appear in pure and applied mathematics (usually not including "elementary" functions).

2 votes
0 answers
68 views

I'd like to prove that $$2\int_0^1 \frac{\operatorname{Li}_2(x(1-x))}{1-x+x^2}\mathrm{d}x=\int_0^1 \frac{\ln x \ln(1-x)}{1-x+x^2}\mathrm{d}x.$$ Ok, someone said that this holds, but I tried really ...
Xiaobao's user avatar
  • 115
2 votes
1 answer
85 views

I am studying a function arising in the analysis of robust aggregation rules in distributed learning, but the question is purely analytical. The function I am facing depends on parameters $a, b > 0$...
Goulifet's user avatar
  • 948
2 votes
1 answer
80 views

Question. Is there a simpler way to prove $$B_{2k+1}(1/4) = \frac{-(2k+1) E_{2k}}{4^{2k+1}}$$ where $B_n(x)$ is the $n$-th Bernoulli polynomial and $E_n$ is the $n$-th Euler number? I have verified ...
Maxime Jaccon's user avatar
2 votes
0 answers
52 views

I think this is a bit hopeless but let me ask just in case. Consider the real and positive function: $$ \hat{f}(\omega) = \sqrt{\frac{\omega}{1-e^{-\frac{\omega}{T}}}} e^{- \frac{\omega^2}{4\Lambda^2}}...
Ben's user avatar
  • 619
0 votes
0 answers
75 views

I am studying the definite integral $$ I = \int_{0}^{1} \frac{\ln(1+x)}{\ln(1-x)}\,dx . $$ The integral does converge: as $x \to 0$, $\ln(1+x) \sim x$ and $\ln(1-x) \sim -x$, so the ratio tends to $-...
Jamal Hanus Jr's user avatar
2 votes
1 answer
140 views

I would like to understand how to make sense of the following divergent series, or at least to identify the appropriate analytic continuation of its general term: \begin{align} \sum_{n=0}^{\infty}\...
Alessandro Pini's user avatar
6 votes
0 answers
98 views

I have been working with the Polylogarithm on several problems and I think it might help if I knew an algebraic/ordinary differential equation (ADE/ODE) which it satisfies (and just for the sake of it!...
Eli Bartlett's user avatar
  • 2,506
1 vote
0 answers
79 views

In my work, an integral of the following type arose: $$\int_0^\infty dx J_l(a x) J_l(b x) \frac{1}{x - c + i 0}.$$ Here $J$ is the Bessel function of the first kind. Assume that $a$, $b$, and $c$ are ...
Emma Anderson's user avatar
4 votes
1 answer
284 views

I would like to prove that $$\int_0^1 \operatorname{Li}_2 \left(\frac{1-x^2}{4}\right) \frac{2}{3+x^2} \,\mathrm dx= \frac{\pi^3 \sqrt{3}}{486}.$$ It’s known that $\Im \operatorname{Li}_3(e^{2πi/3})= \...
Xiaobao's user avatar
  • 115
3 votes
3 answers
268 views

I recently came across the following series with a positive real number $a$: \begin{align} S(a) = \sum _{n=1}^{\infty}(-1)^{n} \frac{n}{\left(n+\sqrt{a+n^2}\right)^2} \end{align} Does anyone know if ...
Alessandro Pini's user avatar
4 votes
0 answers
126 views

By definition, $$ \sum_{n=1}^{+\infty}\frac{1}{n^s} = \zeta(s) \tag{*} $$ when the real part of $s$ is large enough ($>1$). I am also aware that $$ \sum_{n=1}^{+\infty}\frac{\mu(n)}{n^s} = \frac{1}...
Gro-Tsen's user avatar
  • 6,568
9 votes
1 answer
281 views

Some crude numerical experiments led me to stumble upon the amusing result that $$\int_{0}^{\infty} \frac{1}{\operatorname{Bi}(t)^2}\, dt = \frac{\pi}{\sqrt{3}}$$ where $\text{Bi}(x)$ is an Airy ...
Maxime Jaccon's user avatar
1 vote
0 answers
35 views

I try to express the following: $$\text{e}^{(ax^2+bx+c)}(-\hbar\frac{\partial}{\partial x})^n\text{e}^{-(ax^2+bx+c)}$$ in terms of the Hermite Polynomials using the definition of Hermite polynomial ...
R. Bhattacharya's user avatar
17 votes
1 answer
555 views

How can I prove that $$\Omega = \int_{0}^{\infty} \text{Ai}^4(x) \, dx = \frac{\ln(3)}{24 \pi^2}$$ where $\text{Ai}(x)$ is the Airy-function. Using the Fourier integral representation of the Airy ...
Maxime Jaccon's user avatar
1 vote
1 answer
117 views

Evaluate: $$\int \frac{e^x [\operatorname{Ei}(x) \sin(\ln x) - \operatorname{li}(x) \cos(\ln x)]}{x \ln x} \, \mathrm {dx}$$ My approach: $$\int \frac{e^x [\operatorname{Ei}(x) \sin(\ln x) - \...
Andre Lin's user avatar
  • 491

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