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Questions tagged [functional-equations]

The term "functional equation" is used for problems where the goal is to find all functions satisfying the given equation and possibly other conditions. Solving the equation means finding all functions satisfying the equation. For basic questions about functions use more suitable tags like (functions) or (elementary-set-theory).

3 votes
2 answers
419 views

Find all functions $f : \mathbb R \to \mathbb R$ such that: $f (x f ( y ))+y f ( x) = x f ( y ) + f ( x y )$, $\forall\ x , y \in \mathbb{R}$ and b) $\exists M \in \mathbb R$ such that $f(x)<M$ ...
LDPEWIUe's user avatar
  • 105
0 votes
0 answers
35 views

I wanna to prove If for all value of $x$ and $x'$ in real numbers we have; $$f(x) + f(x') = f(x+x')$$ Then $f(x) = Kx.$ I have not any counterexample for this but I can't prove it Thank you for your ...
Mostafa Zeinodini's user avatar
2 votes
1 answer
50 views

Consider a function $f : (0,\infty) \to (0,\infty)$ satisfying the identity $$ f(x^a y^b) \;=\; f(x)^{1/a}\, f(y)^{1/b} \qquad\text{for all } x,y>0 \text{ and all real } a,b\neq 0. $$ This can be ...
J. Zimmerman's user avatar
  • 1,209
-5 votes
0 answers
55 views

If $f$ is a function such it is commutative, continuous and homogeneous and that for any positive variables $a,b$ and $c$, $f(f(a, b), c) = f(f(a, c), b)$ then prove that there must exist a non ...
Suneet Shrotri's user avatar
4 votes
2 answers
120 views

Problem: Find all functions $f:\mathbb{R} \to \mathbb{R}$ such that $f(y^2+1)+f(xy)=f(x+y)f(y)+1$ holds for all $x,y \in \mathbb{R}$. My approach: I have got $f(0)=0,1$. Taking $f(0)=1$, and setting $...
Geometry99's user avatar
2 votes
0 answers
67 views

I am asking this question mainly to probe the knowledge of people already familiar with this problem, otherwise I would advise caution to the unfamiliar trying to use computation, this can be really ...
Evariste's user avatar
  • 2,911
2 votes
1 answer
81 views

I'm looking for a function, $f$, which satisfies \begin{align} tf(x)=f\left(x+\frac{1}{t}-1\right);\quad f(1)=1. \end{align} My attempt: Let $t\rightarrow 1/(1+\log t)$ and $x\rightarrow \log x$, ...
Eli Bartlett's user avatar
  • 2,506
0 votes
1 answer
65 views

Need to find out all the functions $f \colon \mathbb{R} \to \mathbb{R}$ such that $$f(x+y) \leq f(xy).$$ Since $f(x) \leq f(0)$ for every $x \in \mathbb{R}$ and $f(0) \leq f(-x^2)$, it follows that $f(...
Jamai-Con's user avatar
  • 629
16 votes
1 answer
488 views

Suppose $f$ is a holomorphic function defined on a neighborhood of $0$, such that $f(0) = 0$. Let $f^n$ denote the $n$-fold composition of $f$ with itself. If $f^n$ is the identity for some natural ...
EthanK's user avatar
  • 305
-9 votes
0 answers
75 views

Let $\kappa>0$ and $I_\kappa=\bigl(-\tfrac{1}{\kappa},\tfrac{1}{\kappa}\bigr)$. Consider a binary operation $\oplus:I_\kappa^2\to I_\kappa$ with: (A1) $\oplus$ is continuous, strictly increasing in ...
thantikler McIrony's user avatar
7 votes
2 answers
358 views

the problem Find all the functions $f \colon \mathbf R \to \mathbf R$, such that $$f\left(x+\frac{1}{y}\right)+f\left(y+\frac{1}{x}\right)=2f(xy)$$ for all $x,y \in \mathbf R$. my idea Plugging in ...
Pam Munoz Ryan's user avatar
2 votes
1 answer
278 views

Suppose that an unbounded function $f:\mathbb{N} \rightarrow \mathbb{N}$ such that $f(a+b)=f(a)+f(b)$ whenever $f(a+b)$ is the maximum of $f(0), f(1), \dots, f(a+b)$, where $a, b\in \mathbb{N}$. Show ...
Samuel's user avatar
  • 111
1 vote
0 answers
168 views

Suppose a function $f(x)$ is defined on a domain $D$ where $D$ is a subset of $\mathbb{R}$ and $D$ has the property that $x\in{D}$ iff $\frac{1}{x}\in{D}$. Furthermore, suppose $f$ has the following ...
John L's user avatar
  • 1,563
0 votes
0 answers
104 views

Building upon this question, I would like to extend the unanswered question in the comments. That is, do there exist $g,h: \mathbb{N} \rightarrow \mathbb{N}, y \in \mathbb{N}$, such that the following ...
aventador's user avatar
2 votes
0 answers
87 views

I've recently read about discontinuous additive function (i.e. discontinuous solutions of the Cauchy functional equation $f(x+y)=f(x)+f(y)$, $x,y\in\mathbb{R}$) and the following problem came to my ...
Mark Williams's user avatar

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