refactor(changelog): simplify logic for get_oldest_and_newest_rev

commitizen/changelog.py

@@ -318,39 +318,28 @@ def get_oldest_and_newest_rev(
     - `0.1.0..0.4.0`: as a range
     - `0.3.0`: as a single version
     """
-    oldest: str | None = None
-    newest: str | None = None
-    try:
-        oldest, newest = version.split("..")
-    except ValueError:
-        newest = version
-    if not (newest_tag := rules.find_tag_for(tags, newest)):
+    oldest_version, sep, newest_version = version.partition("..")
+    if not sep:
+        newest_version = version
+        oldest_version = ""
+
+    def get_tag_name(v: str) -> str:
+        if tag := rules.find_tag_for(tags, v):
+            return tag.name
         raise NoCommitsFoundError("Could not find a valid revision range.")
 
-    oldest_tag = None
-    oldest_tag_name = None
-    if oldest:
-        if not (oldest_tag := rules.find_tag_for(tags, oldest)):
-            raise NoCommitsFoundError("Could not find a valid revision range.")
-        oldest_tag_name = oldest_tag.name
+    newest_tag_name = get_tag_name(newest_version)
+    oldest_tag_name = get_tag_name(oldest_version) if oldest_version else None
 
-    tags_range = get_smart_tag_range(
-        tags, newest=newest_tag.name, oldest=oldest_tag_name
-    )
+    tags_range = get_smart_tag_range(tags, newest_tag_name, oldest_tag_name)
     if not tags_range:
         raise NoCommitsFoundError("Could not find a valid revision range.")
 
     oldest_rev: str | None = tags_range[-1].name
-    newest_rev = newest_tag.name
-
-    # check if it's the first tag created
-    # and it's also being requested as part of the range
-    if oldest_rev == tags[-1].name and oldest_rev == oldest_tag_name:
-        return None, newest_rev
-
-    # when they are the same, and it's also the
-    # first tag created
-    if oldest_rev == newest_rev:
-        return None, newest_rev
 
-    return oldest_rev, newest_rev
+    # Return None for oldest_rev if:
+    # 1. The oldest tag is the last tag in the list and matches the requested oldest tag
+    # 2. The oldest and the newest tag are the same
+    if oldest_rev == oldest_tag_name == tags[-1].name or oldest_rev == newest_tag_name:
+        oldest_rev = None
+    return oldest_rev, newest_tag_name