-2
\$\begingroup\$

Heyo, I've managed to derive this formula for a cut-off frequency of a passive low-pass filter, but sadly I haven't been able to find any source on the internet which talks about it, so that I could confirm it.

Here's the formula f_cut-off = (sqrt(1-((2R)/R_load)-((R * R)/(R_load * R_load))))/(2piRC) where R_load is the output resistance (think of it like a speaker)

EDIT: The ideal case for the low-pass filter is when there is zero impedance on the output, as shown on the diagram below ideal case

The formula is then f_cut-off = 1/(2piR*C) That is assuming that the voltage changes sinusoidally

For the non-ideal case the diagram is non-ideal case and the formula is as stated earlier.

My question is: is my formula for the cut-off frequency correct, as I have not been able to find any sources on it? Does anybody have a source covering the topic? Thanks in advance!

\$\endgroup\$
2
  • 1
    \$\begingroup\$ Mind showing a schematic? A drawing would be helpful, I think. \$\endgroup\$ Commented Jan 25 at 5:27
  • 2
    \$\begingroup\$ While you're editing your question to include a schematic, please also make it into a question. There's things to comment on, here, but it's not clear what you want to know. \$\endgroup\$ Commented Jan 25 at 6:27

0

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.