✅Day 79 of #100DaysOfLeetCode 1.📌Problem: Can Make Arithmetic Progression From Sequence 2.🟢 Difficulty: Easy 3.📍Topic: Arrays, sorting 4.🎯 Goal: Given an array of numbers, return true if the array can be rearranged to form an arithmetic progression; otherwise, return false. 5.🧠 Key idea: Approach 1: Sort the array to bring numbers in order. Calculate the common difference between the first two elements. Iterate through the array and check if the difference between consecutive elements matches the common difference. If any element does not satisfy the condition, return false; otherwise, return true. #LeetCode #100DaysChallenge #Programming #Coding #Java #Algorithms #CodingPractice #Developer #Tech #CodeNewbie #LearnToCode #ProblemSolving #DataStructures #Arithmetics #InterviewPreparation #CodingSkills #DailyCoding #LinkedInChallenge
Can Make Arithmetic Progression From Sequence: A LeetCode Challenge
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✅Day 69 of #100DaysOfLeetCode 1.📌Problem: Numbers of Digitville 2.🟢 Difficulty: Easy 3.📍Topic: Hashing 4.🎯 Goal: Find two numbers that appear twice in a list where every integer from 0 to n-1 should appear exactly once, but two numbers occur an extra time. 5.🧠key idea: Approach 1: Use nested loops to compare each element with every other element. When a duplicate is found, store it in the result array. Stop after finding two such numbers. #coding #programming #developer #leetcode #100daysofcode #softwareengineering #tech #datastructures #algorithms #hashing #java #problemsolving #learncoding #codenewbie #computerscience #dailychallenge
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🔥 Day 82 of #100DaysDSAChallenge 📌 Topic: Array — Sort Array By Parity ✅ Problem Solved on #LeetCode: 905. Sort Array By Parity (🟢 Easy) 💡 Key Learnings: • Practiced separating even and odd numbers efficiently using two-pointer logic. • Improved understanding of in-place array manipulation for better space optimization. • Strengthened problem-solving speed by reducing complexity to O(n). 🚀 Consistency Builds Confidence: Every challenge you solve makes your logic sharper and your code cleaner. Keep pushing forward 💪 🏷️ #Day82 #100DaysChallenge #100DaysDSAChallenge #LeetCode #Java #CodingChallenge #ProblemSolving #DataStructures #Algorithms #Arrays #Programming #LearningJourney #10kCoders #10000Coders #Consistency #LogicBuilding
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✅Day 59 of #100DaysOfLeetCode 📌Problem: Given a fixed-length integer array arr, duplicate each occurrence of zero, shifting the remaining elements to the right. 🟢 Difficulty: Easy 📍Topic: Array 🎯 Goal: To modify the input array in place by duplicating every zero and shifting other elements accordingly, without returning anything. 🧠key idea: Approach 1: Create a new result array to hold the modified elements. Iterate through the original array; if the element is a zero, add it twice to the result array. Otherwise, add the element once. Finally, copy the contents of the result array back into the original array. #100DaysOfCode #LeetCode #CodingChallenge #Java #DataStructures #Algorithms #ProblemSolving #Developer #SoftwareEngineering #CodeNewbie #Tech #Programming #ArrayManipulation #DuplicateZeros #Day59
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#Day13 2 – Add Two Numbers Solved this classic linked list problem by implementing an efficient algorithm to add two numbers represented as reverse-digit linked lists. 💡 Approach: Used a dummy node to simplify list construction, iterated through both lists while handling different lengths, and maintained a carry value for proper digit summation. The solution elegantly handles cases where lists have different sizes and final carry propagation. #LeetCode #Java #LinkedList #DataStructures #Algorithms #ProblemSolving #Coding #Tech #SoftwareEngineering #DailyCoding #Programming
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✅Day 78 of #100DaysOfLeetCode 1.📌Problem: Find the Difference Given two strings s and t, where t is generated by shuffling s and adding one extra letter at a random position, return the letter that was added. 2.🟢 Difficulty: Easy 3.📍Topic: Strings 4.🎯 Goal: Find the extra character that was added to string t after shuffling and insertion. 5.🧠Key idea: Approach 1: Use the XOR operation to efficiently find the difference. Iterate over both strings, XOR all characters together, and the result will be the added character. This works because XOR-ing identical characters cancels them out, leaving only the unique/added character. #LeetCode #100DaysChallenge #Programming #Coding #CodeNewbie #Java #Tech #SoftwareEngineering #ProblemSolving #Developer #DailyChallenge #HashTable #Algorithms #CodingInterview #LearnToCode
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🔥 Day 80 of #100DaysDSAChallenge 📌 Topic: Array — Contiguous Array ✅ Problem Solved on #LeetCode: 525. Contiguous Array (🟠 Medium) 💡 Key Learnings: • Discovered how to use Prefix Sum and HashMap to efficiently find subarrays with equal 0s and 1s. • Understood that treating 0 as -1 converts the problem into finding the longest subarray with sum = 0. • Learned how tracking the first occurrence of each prefix sum helps identify balanced subarrays. • Strengthened understanding of hash-based optimization, achieving O(n) time and O(n) space complexity. 🚀 Stay Consistent: Each day of problem-solving builds sharper logic and stronger confidence. Small daily progress creates massive long-term growth 💪 🏷️ #Day80 #100DaysChallenge #100DaysDSAChallenge #LeetCode #Java #CodingChallenge #ProblemSolving #DataStructures #Algorithms #Arrays #Programming #LearningJourney #10kCoders #10000Coders #Consistency #LogicBuilding
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🔥 Day 79 of #100DaysDSAChallenge 📌 Topic: Array — Minimum Moves to Equal Array Elements ✅ Problem Solved on #LeetCode: 453. Minimum Moves to Equal Array Elements (🟠 Medium) 💡 Key Learnings: • Understood that incrementing (n−1) elements is equivalent to decrementing one element. • Learned how to derive the formula using the smallest element as a reference point. • Strengthened problem-solving with array manipulation and mathematical reasoning. • Enhanced understanding of optimization — solving in O(n) time and O(1) space. 🚀 Stay Consistent: Daily practice turns effort into skill and skill into success. 🏷️ #Day79 #100DaysChallenge #100DaysDSAChallenge #LeetCode #Java #CodingChallenge #ProblemSolving #DataStructures #Algorithms #Arrays #Programming #LearningJourney #10kCoders #10000Coders #Consistency #LogicBuilding
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✅Day 58 of #100DaysOfLeetCode 1.📌Problem: 2011. Final Value of Variable After Performing Operations 2.✅ Difficulty: Easy 3.📍Topic: Array 4.🎯 Goal: Given an array of strings operations containing a list of operations, return the final value of x after performing all the operations. 5.🧠key idea: Approach 1: Initialize a counter variable to zero. Iterate through the input array of operations. For each operation string, check if it represents an increment ("++X" or "X++"). If it does, increase the counter by one. Otherwise, it's a decrement, so decrease the counter by one. After checking all the operations, return the final value of the counter. #100DaysOfLeetCode #CodingChallenge #Java #ProblemSolving #SoftwareDevelopment #Developer #Programming #CodeNewbie #Tech #DataStructures #Algorithms #Array #LeetCodeChallenge #SoftwareEngineer #DailyChallenge
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Day 8 of Mastering DSA Patterns: Container With Most Water : Another day, another DSA challenge conquered. Today's focus was on the Two Pointer technique, and I solved the LeetCode classic: Container With Most Water. This problem is a fantastic illustration of how a clever choice of algorithm can drastically reduce time complexity. Instead of checking every pair of lines an O(n^2) brute-force solution), the Two-Pointer approach offers an efficient O(n) solution: 1.Start pointers at the farthest ends of the array. 2.Calculate the area. 3.The area is limited by the shorter line. To potentially find a larger area, you must try to increase the height. Therefore, move the pointer of the shorter line inward. Moving the longer line's pointer would only decrease or keep the height the same, offering no guaranteed improvement. 4.Repeat until the pointers meet. It's a subtle but powerful optimization! #DSA #DataStructures #Algorithms #ContainerWithMostWater #LeetCode #CodingChallenge #TwoPointers #Java #Programming #Tech
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✅Day 57 of #100DaysOfLeetCode 1.📌Problem: 350. Intersection of Two Arrays II 2.🟢 Difficulty: Easy 3.📍Topic: Arrays 4.🎯 Goal: Given two integer arrays, nums1 and nums2, return an array of their intersection. Each element in the result must appear as many times as it shows in both arrays, and you may return the result in any order. 5.🧠key idea: Approach 1: Sort both arrays and use a two-pointer technique. Initialize two pointers, one for each array, starting at the beginning. If the elements at the current pointers are the same, add the element to the result and advance both pointers. If the element in the first array is smaller, advance its pointer. If the element in the second array is smaller, advance its pointer. Continue until one of the pointers reaches the end of its array. #100DaysOfLeetCode #LeetCode #CodingChallenge #Java #DataStructures #Algorithms #SoftwareDevelopment #Programming #CodeNewbie #Tech #Developer #SoftwareEngineer #ProblemSolving #TwoPointers #Array
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