Question: In a one day international cricket match, considering no extras(no wides, no 'no' balls, etc.) and no overthrows.
What is the maximum number of runs that a batsman can score in an ideal case ?
Note:"Here we assume ideal and little practical scenario. We assume that batsman can not run for more than 3 runs in a ball, as otherwise there is no limit, he can run infinite runs(theoretically) in a ball, as far as opposite team does not catch the ball."
Answer:49*(6*5+3)+(6*6)= 1653From Over 1 to 49:
1st ball:- 6 runs(hit six)
2nd ball:- 6 runs(hit six)
3rd ball:- 6 runs(hit six)
4th ball:- 6 runs(hit six)
5th ball:- 6 runs(hit six)
6th ball:- 3 runs(took 3 runs between the wickets and take back the strike)
= >49*(6*5+3)
50th Over:
Hit six sixes in a row.
= >6*6
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