calling .each{} on IntRange returns the range not each integer

Question

I think I've got some funny expectations... I want to iterate the numbers from 1 to 10. As a while loop it goes like this:

def countMe = 1
while (countMe<11) {
  println countMe
  countMe++
}

I was expecting that the following would do this also:

[1..10].each { println it }

But it actually prints the IntRange, not each Integer in the range. What is the (syntactically) closest way to my [x..y].each{} fantasy to get each of a list of numbers?

Eric · Accepted Answer · 2012-09-15 00:05:28Z

114

Use parentheses not brackets:

(1..10).each{println it}

[1..10] is a list of length 1 containing a single range.

answered Sep 15, 2012 at 0:05

Eric

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1 Comment

Vorg van Geir Over a year ago

You need to remember [1..10] only means a range when it's a subscript AFTER another variable. When it stands alone, then it's a LIST OF a range. These little inconsistencies arise because Groovy tries hard to extend Java's syntax with its own additions.

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