Timeline for answer to How can I format a duration with std::println? by Drew Dormann
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| yesterday | history | edited | Drew Dormann | CC BY-SA 4.0 |
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| yesterday | history | edited | Drew Dormann | CC BY-SA 4.0 |
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| yesterday | history | edited | Drew Dormann | CC BY-SA 4.0 |
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| yesterday | comment | added | Drew Dormann | @Caleth yes — matching the behavior of C++ internal types, if either operand of a division is floating point, the result will be floating point. You can certainly leverage that to get the behavior that you want. | |
| yesterday | vote | accept | Angle.Bracket | ||
| yesterday | comment | added | Caleth | Interestingly, there's a difference between how these format floating point durations: godbolt.org/z/nWfq1PG5v | |
| yesterday | history | edited | Drew Dormann | CC BY-SA 4.0 |
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| yesterday | history | answered | Drew Dormann | CC BY-SA 4.0 |