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Mar 19, 2024 at 7:53 comment added alanf "This shows that classical mechanics cannot be regarded as emerging from quantum mechanics-at least in this sense-upon straightforward application of the limit $\hbar\to 0$."Quote from the abstract. I have explained the actual classical limit in my answer.
Mar 19, 2024 at 4:38 comment added Guillaume Laporte @alanf: The paper you mentioned states various ways of taking limits in Schrodinger's equation which seem to have different outcomes; this indicates a problem with the approach I would guess.. In the question I asked, I assume there are localized particles initially (page 9); and that we can use propagators to evolve them, changing their Planck's constant along the way. You gave an answer to the first part, thank you : ) what about the end when $\hbar \to 0$ and then $\hbar = 0$ in all correlation functions? Going back in time, the limit exists and leads to the initial localized particles..
Mar 18, 2024 at 22:00 comment added alanf @GuillaumeLaporte $\hbar\to 0$ isn't the classical limit. It is neither necessary nor sufficient to produce classical behaviour as I explained above. For more discussion of the $\hbar\to 0$ limit see arxiv.org/abs/1201.0150
S Mar 18, 2024 at 18:31 history suggested Stephane Bersier CC BY-SA 4.0
Minor fixes, and "more or" -> "more-or-less"
Mar 18, 2024 at 18:10 comment added Guillaume Laporte I added a function (the bump function) to show that the constant can effectively start smoothly from zero, to non-zero value, and then back smoothly to zero. Everything should evolve nicely and continuously (even smoothly); from classical to quantum; and then from quantum to classical. But I still don't know what happens when the constant goes back to zero, what happens to the branches in the many-worlds at the end
Mar 18, 2024 at 18:06 review Suggested edits
S Mar 18, 2024 at 18:31
Mar 18, 2024 at 18:00 comment added More Anonymous With dimensional constants the best one can do is take the ratio of the limit (which is dimensionless) to zero
Mar 18, 2024 at 15:20 comment added hyportnex It is not the same if one assumes discontinuity in said limit; either way, continuity or discontinuity, is an assumption.
Mar 18, 2024 at 10:52 comment added alanf "in the limit when Planck's constant goes to zero" is not the same as just setting it to zero
Mar 18, 2024 at 10:23 comment added hyportnex but a zero is zero at all scales
Mar 18, 2024 at 9:46 history answered alanf CC BY-SA 4.0