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Jan 12, 2022 at 14:33 history reopened Bill Dubuque polynomials
Jan 12, 2022 at 7:05 history closed Jyrki Lahtonen polynomials Duplicate of Gre Question Complex Number (plug and chug) [duplicate]
Jan 10, 2022 at 8:52 history edited Bill Dubuque CC BY-SA 4.0
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May 15, 2020 at 19:07 history edited Bill Dubuque
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Nov 24, 2019 at 19:47 history edited Bill Dubuque CC BY-SA 4.0
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Jul 8, 2019 at 13:31 history edited nonuser
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Jun 10, 2019 at 0:01 history tweeted twitter.com/StackMath/status/1137872269076836352
Jun 6, 2019 at 20:23 audit First posts
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May 24, 2019 at 17:50 audit First posts
May 24, 2019 at 17:50
May 17, 2019 at 9:10 comment added Henrik Erlandsson All methods that have been taught as part of the course are eligible for test questions, period. If the teacher blundered, a top student may bring it up; the rest will feel bad for not knowing what they shouldn't. Thing is, a top student couldn't solve this if he wasn't taught it. With the comments from college students and PhDs here, it seems bounceback's answer addresses the question closest, most seem to just solve the problem which is not what your question is about, as I read it.
May 17, 2019 at 6:25 audit First posts
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May 16, 2019 at 16:35 comment added PersonX What kind of test? Is this part of a math competition, or a classroom precalculus exam?
May 16, 2019 at 14:39 history edited Bill Dubuque
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May 16, 2019 at 13:49 comment added Bill Dubuque I added some explicit examples to the end of my answer to emphasize the ubiquity of that simple idea.
May 16, 2019 at 8:49 history edited joeblack CC BY-SA 4.0
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May 16, 2019 at 8:48 vote accept joeblack
May 15, 2019 at 21:06 comment added LarsH I'm probably missing something, but... The above trick seems to show that when $Q(x) = 0$, $P(x) = Q(x)$. But (a) the original question didn't specify that $Q(x) = 0$; how do we know that the answer $P(x)\equiv\mathbf0\pmod{Q(x)}$ applies to other cases? and (b) the original question asks, "what is the remainder of $𝑃(𝑥)$ divided by $𝑄(𝑥)$?" but the answer given here says let $Q(x) = 0$; doesn't that mean that the remainder is not defined? en.wikipedia.org/wiki/Remainder#Polynomial_division
May 14, 2019 at 23:33 comment added Mark My approach would be to observe that the exponents on P(x) look like they're set up to produce an elegant answer. The common elegant answers are "1" and "0". Since the "+1"s on the polynomials are clearly intended to cancel out, the answer must be "0".
May 14, 2019 at 17:35 history edited nonuser
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May 14, 2019 at 15:48 comment added logarithm One observation is that in that question the step of 'multiplying both sides by $x-1$' is only presentation and doesn't really represent any advantage for solving the problem. What is really important is observing that the roots of $Q$ are the fifths roots of $1$ besides $1$, or that is a factor of $x^5-1$. There are many ways to compute this remainder that are simple to do in a short time. So, don't include that 'multiplying by $x-1$' as part of what was required for the students to solve the problem
May 14, 2019 at 6:59 history edited joeblack CC BY-SA 4.0
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May 14, 2019 at 6:52 vote accept joeblack
May 14, 2019 at 6:55
May 14, 2019 at 3:54 answer added Hari Shankar timeline score: 23
S May 14, 2019 at 0:26 history suggested ReinstateMonica3167040 CC BY-SA 4.0
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May 13, 2019 at 23:34 answer added Henry timeline score: 10
May 13, 2019 at 21:24 answer added Sam Benner timeline score: 12
May 13, 2019 at 20:23 history became hot network question
May 13, 2019 at 19:07 answer added nonuser timeline score: 46
May 13, 2019 at 19:05 answer added Nightgap timeline score: 4
May 13, 2019 at 19:03 history edited Bernard CC BY-SA 4.0
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May 13, 2019 at 18:58 answer added DanLewis3264 timeline score: 30
May 13, 2019 at 18:49 answer added Bill Dubuque timeline score: 56
May 13, 2019 at 18:46 history edited joeblack CC BY-SA 4.0
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May 13, 2019 at 18:38 history asked joeblack CC BY-SA 4.0