Timeline for The longest repeating decimal that can be created from a simple fraction
Current License: CC BY-SA 4.0
21 events
| when toggle format | what | by | license | comment | |
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| Nov 16, 2021 at 23:47 | review | Suggested edits | |||
| Nov 17, 2021 at 0:23 | |||||
| Jan 31, 2020 at 16:21 | answer | added | smichr | timeline score: 2 | |
| Nov 30, 2019 at 22:28 | history | edited | Jam | CC BY-SA 4.0 |
title in plain english and added tag
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| Oct 17, 2019 at 19:30 | history | protected | CommunityBot | ||
| Oct 9, 2019 at 14:39 | comment | added | PlsWork |
What's the general answer if the numerator is less than m and denominator less than n?
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| May 28, 2018 at 0:41 | answer | added | q-l-p | timeline score: 3 | |
| S May 27, 2018 at 19:05 | history | suggested | q-l-p | CC BY-SA 4.0 |
made the question clearer and more concise
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| May 27, 2018 at 18:54 | review | Suggested edits | |||
| S May 27, 2018 at 19:05 | |||||
| Nov 18, 2016 at 3:14 | comment | added | Steven Alexis Gregory | The repeating part is called the repetend. You want to know what the longest possible repetend is. | |
| Nov 18, 2016 at 3:05 | answer | added | ilovemaths169 | timeline score: 0 | |
| Apr 28, 2015 at 1:36 | answer | added | Erwin Engert | timeline score: 0 | |
| Apr 28, 2013 at 5:48 | review | Close votes | |||
| Apr 28, 2013 at 9:01 | |||||
| Apr 28, 2013 at 4:59 | answer | added | Seth | timeline score: 0 | |
| Jan 27, 2013 at 3:49 | comment | added | Gerry Myerson | If you want a fraction with a period of exactly $9998$, then you need to find a denominator which divides $10^{9998}-1$ and doesn't divide $10^r-1$ for any $r$, $1\le r\le9997$. Theory guarantees there are some, but they may have hundreds or thousands of digits. | |
| Jan 27, 2013 at 1:57 | vote | accept | user1822824 | ||
| Jan 27, 2013 at 1:42 | review | First posts | |||
| Jan 27, 2013 at 1:46 | |||||
| Jan 27, 2013 at 1:32 | answer | added | Gerry Myerson | timeline score: 11 | |
| Jan 27, 2013 at 1:32 | comment | added | user1822824 | I'm looking for a fraction that will create a period of repetition of 9,998 repeating digits? | |
| Jan 27, 2013 at 1:30 | comment | added | user1822824 | I mean the longest period of repetition. For 1/97 I get 96 repeating digits. | |
| Jan 27, 2013 at 1:28 | comment | added | guest196883 | Could you explain what you mean by the largest possible repeating decimal? Because all fractions will produce a repeating decimal and the largest would therefore be 9999/1 = 9999. Do you mean the longest period of repetition? | |
| Jan 27, 2013 at 1:26 | history | asked | user1822824 | CC BY-SA 3.0 |