Display query in the URL on failed request

Signed-off-by: Emmanuel Ferdman <emmanuelferdman@gmail.com>

Author: emmanuel-ferdman

src/hackingBuddyGPT/capabilities/http_request.py

@@ -67,7 +67,7 @@ def __call__(
                 allow_redirects=self.follow_redirects,
             )
         except requests.exceptions.RequestException as e:
-            url = self.host + ("" if path.startswith("/") else "/") + path + ("?{query}" if query else "")
+            url = self.host + ("" if path.startswith("/") else "/") + path + (f"?{query}" if query else "")
             return f"Could not request '{url}': {e}"
 
         response_headers = "\r\n".join(f"{k}: {v}" for k, v in resp.headers.items())