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Use parse_qsl(keep_blank_values=True) and urlencode(doseq=True), override keys without dropping duplicates and keep original key order where it can be seen that possible.

Given url: http://x?a=1&a=2&b=&c=3
modify_url_query(url, a=[4,5]) => http://x?a=4&a=5&b=&c=3
modify_url_query(url, d=7) => http://x?a=1&a=2&b=&c=3&d=7
modify_url_query(url, b="") preserves empty value.

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- Fix 'compatability' to 'compatibility' in email.py and screenshot_test.py
- Fix 'accomodate' to 'accommodate' in email.py and log.py
- Fix 'dependant' to 'dependent' in exploreReducer.js
- Fix 'begining' to 'beginning' in UPDATING.md
- Fix 'occured' to 'occurred' in Header.test.tsx
- Fix 'succesful' to 'successful' in test_connection.py
…y_url_query

Use parse_qsl(keep_blank_values=True) and urlencode(doseq=True); override keys without dropping duplicates and keep original key order where it can be seen that possible.
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bito-code-review bot commented Oct 31, 2025

Code Review Agent Run #b56472

Actionable Suggestions - 0
Additional Suggestions - 2
  • superset/utils/urls.py - 2
    • Use modern union syntax in isinstance · Line 56-56
      Multiple `isinstance` calls use tuple syntax instead of modern union syntax. On lines 56 and 59, replace `(list,tuple)` with `list | tuple` for better readability and modern Python style.
      Code suggestion
       @@ -55,57 +55,57 @@
      -            new=[(k,str(x)) for x in v] if isinstance(v, (list,tuple)) else [(k,str(v))]
      +            new=[(k,str(x)) for x in v] if isinstance(v, list | tuple) else [(k,str(v))]
    • Use elif instead of else if · Line 58-58
      Use `elif` instead of `else` followed by `if` to reduce indentation and improve readability.
      Code suggestion
       @@ -57,63 +57,62 @@
      -        else:
      -            if isinstance(v,(list,tuple)):
      -                pairs.extend((k,str(x)) for x in v)
      -            else:
      -                pairs.append((k,str(v)))
      +        elif isinstance(v, list | tuple):
      +            pairs.extend((k,str(x)) for x in v)
      +        else:
      +            pairs.append((k,str(v)))
Review Details
  • Files reviewed - 7 · Commit Range: d7a1654..8cecb74
    • superset-frontend/src/components/GridTable/Header.test.tsx
    • superset-frontend/src/explore/reducers/exploreReducer.js
    • superset/commands/database/test_connection.py
    • superset/reports/notifications/email.py
    • superset/utils/log.py
    • superset/utils/urls.py
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@akshatsinha0
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@dosubot dosubot bot added the change:backend Requires changing the backend label Oct 31, 2025
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Review by Korbit AI

Korbit automatically attempts to detect when you fix issues in new commits.
Category Issue Status
Performance Inefficient double iteration over query parameters ▹ view
Performance Expensive list slice insertion operation ▹ view
Files scanned
File Path Reviewed
superset/utils/urls.py
superset/reports/notifications/email.py
superset-frontend/src/explore/reducers/exploreReducer.js
superset/utils/log.py

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Comment on lines +52 to +55
idxs = [i for i,(kk,_) in enumerate(pairs) if kk==k]
if idxs:
pos = min(idxs)
pairs = [(kk,vv) for (kk,vv) in pairs if kk!=k]
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Inefficient double iteration over query parameters category Performance

Tell me more
What is the issue?

The code performs two separate iterations over the pairs list - first to find indices, then to filter out matching keys, resulting in O(n²) time complexity when updating multiple parameters.

Why this matters

This approach scales poorly with large query strings or when updating many parameters, as each parameter update requires scanning the entire pairs list twice.

Suggested change ∙ Feature Preview

Use a single pass approach to build the new pairs list while tracking positions, or use a dictionary-based approach for better performance:

result_pairs = []
for i, (kk, vv) in enumerate(pairs):
    if kk not in kwargs:
        result_pairs.append((kk, vv))
    elif kk in kwargs and kk not in processed:
        # Insert new values at first occurrence position
        v = kwargs[kk]
        new = [(kk, str(x)) for x in v] if isinstance(v, (list, tuple)) else [(kk, str(v))]
        result_pairs.extend(new)
        processed.add(kk)
Provide feedback to improve future suggestions

Nice Catch Incorrect Not in Scope Not in coding standard Other

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pos = min(idxs)
pairs = [(kk,vv) for (kk,vv) in pairs if kk!=k]
new=[(k,str(x)) for x in v] if isinstance(v, (list,tuple)) else [(k,str(v))]
pairs[pos:pos]=new
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Expensive list slice insertion operation category Performance

Tell me more
What is the issue?

Using slice assignment to insert elements at a specific position in a list has O(n) time complexity due to the need to shift all subsequent elements.

Why this matters

This operation becomes expensive for large query strings as it requires moving all elements after the insertion point, contributing to the overall poor performance of the function.

Suggested change ∙ Feature Preview

Build the result list incrementally without slice insertions, or use a more efficient data structure like collections.deque for insertions, then convert back to list at the end.

Provide feedback to improve future suggestions

Nice Catch Incorrect Not in Scope Not in coding standard Other

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