Timeline for answer to Help understanding amplitude modulation circuit by Andy aka
Current License: CC BY-SA 4.0
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| when toggle format | what | by | license | comment | |
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| 16 hours ago | vote | accept | Gabriel Stan | ||
| 16 hours ago | comment | added | Gabriel Stan | Thanks a lot, I think I understand it now. | |
| 17 hours ago | comment | added | Andy aka | @GabrielStan the two resistors also form a potential divider so thinks reduce a bit more. I added the waveforms at the output of the diode for ease of understanding. | |
| 17 hours ago | history | edited | Andy aka | CC BY-SA 4.0 |
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| 17 hours ago | comment | added | Gabriel Stan | Thanks a lot for this thorough explanation. For the last part, I did mean the modulated carrier (Vout), it goes from -0.75V to 0.75V, while the “message” (V1) goes from -1.25V to 1.25V. | |
| 17 hours ago | history | edited | Andy aka | CC BY-SA 4.0 |
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| 17 hours ago | history | answered | Andy aka | CC BY-SA 4.0 |