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lang-bash
unsetet al from being overwritten.-fargument tounsetdoesn't it? Otherwise if both a variable and function named the same as a builtin are defined thenunsetwill pick the variable to unset first. Also this fails if any of the obscuring functions is setreadonlydoesn't it? (Though that's detectable and can be made a fatal error.) Also this misses the[builtin it seems.\unset -f unsetmakes sense, given it will be done in the read loop. Ifunsetis a function your\unsetwould normally resolve to it instead of the builtin, but you can use\unsetsafely so long as POSIX mode is in effect. Explicitly calling\unset -fon[,., and:might be a good idea though, as your regex excludes them. I would also add-fto the\unsetin the loop, and would\unset POSIXLY_CORRECTafter the loop, instead of before.\unalias -a(after\unset -f unalias) also allows one to safely forego the escape on subsequent commands.[[ ${POSIXLY_CORRECT?non-POSIX mode shell is untrusted}x ]], this will cause a non-interactive script to exit with the error indicated if the variable is unset, or continue if it is set (empty, or any value).\unset" ... It should be noted that quoting of any character(s) would work to avoid the alias expansion, not just the first.un"se"twould work just as well, abeit less readable. "The first word of each simple command, if unquoted, is checked to see if it has an alias." –Bash Ref